Someone can explain me why $tan(-\frac{\pi}4+\arctan x)=\frac{x-1}{x+1}$??
I try to understand it, bot I don't understand how to came from one side to the other...
Thank you!
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2$\begingroup$ Do you know the addition formula for $\tan$? $\endgroup$ – Daniel Fischer♦ Mar 28 '14 at 22:11
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$\begingroup$ @DanielFischer, I don't think so... $\endgroup$ – CS1 Mar 28 '14 at 22:12
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4$\begingroup$ $$\tan(a\pm b) = \frac{\tan(a)\pm\tan(b)}{1\mp\tan(a)\tan(b)}.$$ $\endgroup$ – Cameron Williams Mar 28 '14 at 22:13
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$\begingroup$ Thank you!!! Both of you help me a lot!! $\endgroup$ – CS1 Mar 28 '14 at 22:14
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1$\begingroup$ You're very welcome :) $\endgroup$ – Cameron Williams Mar 28 '14 at 22:15
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We know that $$\tan(a-b)=\dfrac{\tan a-\tan b}{1+\tan a\tan b}$$ So, let $b=\pi/4,a=\arctan x$. Then, $$\tan(\arctan x-\pi/4)=\dfrac{\tan \arctan x-\tan \pi/4}{1+\tan \arctan x\tan \pi/4}=\dfrac{x-1}{1+x}$$
