0
$\begingroup$

I have this equation and I'm trying to solve for $M$ but it is not working out. Can someone please help me?

$$ \frac{M}{M^2 + 1} = \epsilon .$$

$\endgroup$
  • 4
    $\begingroup$ $\epsilon M^2 - M + \epsilon = 0$ ? $\endgroup$ – Claude Leibovici Mar 28 '14 at 6:46
2
$\begingroup$

Multiply the denominator out to get $M=\epsilon M^2+\epsilon$ and then use the quadratic equation.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.