I am completely confused as to what to do, I don't understand how to factor with the brackets.


Also state factoring used... Please and thank you. Steps?!?!

  • $\begingroup$ What do you know about $a$? Is it an arbitrary value? Also you can trivially factor out an $x^2$ $\endgroup$ – ruler501 Mar 26 '14 at 19:13
  • $\begingroup$ Try factoring out the greatest common factor. $\endgroup$ – John Habert Mar 26 '14 at 19:13
  • $\begingroup$ @Amzoti can't that be factored further? $\endgroup$ – ruler501 Mar 26 '14 at 19:17

We can treat $(a+10)$ as just another variable, like $x$. We see that $(a+10)$ occurs in every term, and so we can factor it out.

Also, there is a factor $x^2$ in every term.

Also, every term can be divided evenly by $6$.

The largest factor common to each term is thus $6 \cdot x^2 \cdot (a+10)$. In this way we can write the factorized expression as:

$$6x^2(a+10) \cdot \left( 7x^5 + 10x^3 - 4 \right)$$


$(a+10)$ is just a term. Distribute it out and you are left with $(a+10)$ times a polynomial in $x$. Now there is a power of $x$ common to all three terms, so distribute that power of $x$ out. Now look at the coefficients-do they have a common factor?


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