My book somehow got from those top two equations in the picture and solved for v'2(t) + v'1(t). I don't see how they did this? Can anyone see the trick for this type of problem?
$\begingroup$
$\endgroup$
asked Mar 17 '14 at 16:39
Add a comment
|
$\begingroup$
$\endgroup$
1
Multiply the top equation by $\sin{t}$ and the bottom equation by $\cos{t}$. Add.
answered Mar 17 '14 at 16:50
-
$\begingroup$ Oh my gosh! I can't believe I didnt see that... $\endgroup$ – Jeremy Rowler Mar 17 '14 at 16:55
