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My book somehow got from those top two equations in the picture and solved for v'2(t) + v'1(t). I don't see how they did this? Can anyone see the trick for this type of problem?

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Multiply the top equation by $\sin{t}$ and the bottom equation by $\cos{t}$. Add.

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  • $\begingroup$ Oh my gosh! I can't believe I didnt see that... $\endgroup$ – Jeremy Rowler Mar 17 '14 at 16:55

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