Relationship between $|a_{i,j}|$ and $|\alpha^{|i-j|} a_{i,j}|$ What is the relationship between the determinants of the square matrices of equal dimensions $\mathbf{A}$ and $\mathbf{B}$ where each element of $\mathbf{B}$ is equal to the corresponding element of $\mathbf{A}$, times some constant ($\alpha$) raised to the absolute value of the difference of the row and column numbers? E.g. the $3 \times 3$ case is:
$$ \mathbf{A} = \begin{vmatrix}
a_{1,1} & a_{1,2} & a_{1,3} \\
a_{2,1} & a_{2,2} & a_{2,3} \\
a_{3,1} & a_{3,2} & a_{3,3}
\end{vmatrix}
\qquad\&\qquad\mathbf{B} = \begin{vmatrix}
\alpha^0 a_{1,1} & \alpha^1 a_{1,2} & \alpha^2 a_{1,3} \\
\alpha^1 a_{2,1} & \alpha^0 a_{2,2} & \alpha^1 a_{2,3} \\
\alpha^2 a_{3,1} & \alpha^1 a_{3,2} & \alpha^0 a_{3,3}
\end{vmatrix} $$
I haven't been able to get beyond trivial answers that are directly obvious from the problem statement.
 A: Expanding gives
$$\begin{vmatrix}
\alpha^0 a_{11} & \alpha^1 a_{12} & \alpha^2 a_{13} \\
\alpha^1 a_{21} & \alpha^0 a_{22} & \alpha^1 a_{23} \\
\alpha^2 a_{31} & \alpha^1 a_{32} & \alpha^0 a_{33}
\end{vmatrix}$$
$$=a_{11}a_{22}a_{33}\alpha^0-(a_{11}a_{32}a_{23}+a_{21}a_{12}a_{33})\alpha^2+(a_{21}a_{32}a_{13}+a_{31}a_{12}a_{23}-a_{31}a_{22}a_{13})\alpha^4.$$
This doesn't really have any relationship with $\det A$ except for trivial equality when $\alpha=\pm1$. One "nontrivial" thing that can be done is define $|\sigma-\rho|=\sum_{k=1}^n |\sigma(k)-\rho(k)|$ for permutations $\sigma,\rho$, in which case the Leibniz formula can be augmented to read (for the $n\times n$ case)
$$\det B=\sum_{\sigma}(-1)^{\sigma}\alpha^{|\sigma-\mathrm{Id}|}\prod_{j=1}^n a_{j,\sigma(j)}.$$
If instead we use the signed differences between column and row index, the matrix $B$ is the result of multiplying the second and third rows by $\alpha$ and $\alpha^2$ respectively and the second and third columns by $\alpha^{-1}$ and $\alpha^{-2}$ respectively of the matrix $A$, which preserves the determinant. (The multi-dimensional generalization obtains in the same straightforward manner.)
