How to simplify this easy expression $3\cdot(4x)^2 \cdot 4$
How do I simplify that expression? I know it's easy but I suck at math so a detailed explanation would be much appreciated. 
 A: We are given $3(4x)^2 \cdot 4 $, and so here (because we have multiple operations) we must follow the order of operations, starting with parentheses. The parentheses in this case can't be simplified further, and so now we move on to exponents: $$ 3\cdot (4c)^2 \cdot 4  = 3 \cdot (4c)(4c) \cdot 4 \  .$$
Here we can take advantage of the fact that multiplication is associative and communicative by re-arranging the expression: $$\begin{align} 3 \cdot (4c)(4c) \cdot 4 &=3 \cdot 4 \cdot c \cdot 4 \cdot c \cdot 4\\ &= 3 \cdot 4 \cdot 4 \cdot 4 \cdot c \cdot c\end {align}$$
and because we know that $3 \cdot 4 \cdot 4 \cdot 4 = 192$ and that $c \cdot c = c^2$ we can say $$3\cdot (4c)^2 \cdot 4 = 192c^2$$
A: Recall that $(ab)^2 = a^2 b^2$, and after using that, it is simply a matter of multiplication, remembering that multiplication is commutative, so $a \cdot b = b\cdot a$:
$$3(4x)^2 \cdot 4 \; = \; 3(4)^2\cdot (x)^2 \cdot 4 \;= \; 3\cdot 16 x^2 \cdot 4 \;= \;192x^2$$
A: 3⋅ $(4x)^2$⋅4
We know that 3 x 4 is 12.
12 x $(4x)^2$
Then we "split" the power of 2.
12 x (16(x^2))
Then 192x^2
