# How to solve a inequality with fractions and roots in denominator and numerator

The inequality is like that: $$\sqrt{\frac{3x+1}{2}}>1$$ I have no idea how should i begin with it.

• Start by squaring the whole thing? – user2345215 Mar 5 '14 at 11:12
• a condition must be given, from which you have to find this, so check it – mahavir Mar 5 '14 at 11:40

Hint: The value $\sqrt a$ is greater than $1$ iff $a>1$.