The inequality is like that: $$ \sqrt{\frac{3x+1}{2}}>1 $$ I have no idea how should i begin with it.

  • 2
    $\begingroup$ Start by squaring the whole thing? $\endgroup$ – user2345215 Mar 5 '14 at 11:12
  • $\begingroup$ a condition must be given, from which you have to find this, so check it $\endgroup$ – mahavir Mar 5 '14 at 11:40

Hint: The value $\sqrt a$ is greater than $1$ iff $a>1$.


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