Approximating Logs and Antilogs by hand I have read through questions like Calculate logarithms by hand and and a section of the Feynman Lecture series which talks about calculation of logarithms.
I have recognized neither of them useful for my purpose which is to quickly calculate logarithms of base $10$ upto $4$ digit accuracy (I believe 4 is the goldilocks number in this case) .
I wish to find things like $\log_{10}(2) \approx 0.3010$ quickly without using a calculator or log table. Why? Because I want to be free from carrying them around and losing them all day. Plus, they're not always available when I need them (you can guess why).
My main purpose is to approximate the answers of very large and very small results of time consuming calculations.
Logarithms make that job much easier for me. For example,
$$\frac{87539319}{1729} \approx 10^{7.942 - 3.237}  = 10^{4.705} = 5.069*10^4$$
According to Wolfram (Yup, I'm that lazy) the answer is, $50630.0\overline{283400809716599190}$.
Yes, I've over estimated by around $60$ but thanks to a log table, I did that approximation as fast as it took Wolfram to load the precise answer in my browser. But, without a log table, dividing itself would have me executing an iterative convergence just to find the multiples. (1729*2 = too low, 1729*8= too high ... this must be so intuitive for most of you)
So, a quick approximation method for logarithms would be really helpful to me.

Also, a good way to find antilogs will be nice as well.
I just realized that I can't compute decimal powers.
$$\Large 10^{0.3010} = 10^{0.3}*10^{0.001} = \sqrt[10]{1000} * \sqrt[1000]{10} = \text{Calculator Required}$$
I checked "
How to calculate a decimal power of a number"
but alas, the thing which came closest to what I needed required a calculator for an intermediate step. Defeats the purpose, I know. 
If I can't find the antilog, the whole point of having a quick way to find the logarithm would be lost. 

I hope you can help.
 A: Jacques Laporte has a page explaining some algorithms that work digit by digit. For other functions (e.g. trigonometric and hyperbolic) there is the class of CORDIC algorithms. Such algorithms were used in the first HP calculators, as they need very modest hardware.
A: For quick-and-dirty approximations, I'm fond of the musical logarithms (writeup by Sanjoy Mahajan of work due to I. J. Good, who credits his father).  Essentially this boils down to a mathematical fact:


*

*$2^{10} \approx 10^3$, and taking 120th roots, $2^{1/12} \approx  10^{1/40}$.


and a "musical" fact:


*

*many rational numbers with small numerator and denominator can be approximated as powers of $2^{1/12}$.


I call this a "musical" fact because $2^{1/12}$ is the frequency ratio corresponding to an (equal-tempered) semitone.
For example: $3/2$ is the frequency ratio corresponding to the musical interval of a perfect fifth, which is seven semitones; thus $3/2 \approx 2^{7/12} \approx 10^{7/40}$ and so $\log_{10} 3/2 \approx 7/40$.
A: As you want to do calculations by hand, you are merely asking how to build a table of logarithms.
There are at least two ways:


*

*Computing $\sqrt{10}$, then the square root of it, etc. until the result is small enough to do an approximation. That's described in Feynman lecture.

*Using series, for example $\ln (1+t)=t-\frac12t^2+\frac13t^3+\cdots$. There is a way to use them to compute approximations of $\ln k$ for $k\in\{2,3,5,7\}$. With them you compute $\ln 10$ and its inverse, and it helps you compute decimal logs from natural log. Then by applying the series to fractions $\frac{n+1}{n}$, you can, step by step, compute all logarithms you need.


I can give some more details if necessary.
Combining the series for $\ln(1+t)$ and $\ln(1-t)$, you get a series with only odd terms, so it's faster to use.
There are also methods to compute logarithms of trigonometric functions: trigonometric formulas are very useful to simplify many computations by logarithms.
There are also special tables, like a $20$ decimals one in Hoüel tables of logarithms, to compute the log or antilog of a number to $20$ decimal places, with only a very small table (one page) with logs of numbers $1+d\cdot10^k$.
Now, all of these need an unbelievable amount of time to build a table of logarithms, even if you want only logs of numbers from $100$ to $1000$ to four decimals. And there is no simple way to compute just one logarithm only by hand. There are the series above, polynomial approximations, and probably other ways, but nothing as easy to use as a table. And algorithms used by computers are far from usable by hand.
So, if you insist on not using a calculator or a computer, which I perfectly understand, I still wonder why you want to do what took decades to mathematicians of the past to build reliable tables. Doing it yourself would be an intersting endeavor, but I can't imagine it's only to have the table at hand: then, why not simply use a well known table, like those by Schrön, Callet or Dupuis, among others? Doing it yourself, and alone, is the best way to make many computational mistakes a get an unreliable table. Notice that there were mistakes even in well-known tables (I found a list of errata for Schrön's table for example), and the verification step is certainly not the least important.
Notice old tables are still available as used books (the latest were published in the eighties, and are in very good condition, but even old ones from the late 19th century are in fairly good shape). You can even find slide rules - even new ones, as I bought several on Faber-Castell's site, never open (very old stock I guess).
There are also many scanned tables on the net, and this nice site.
I'd be glad to develop on any part, but I would like to understand what you really want. And notice, if there was a usable trick by hand with no table, no slide rule, and nothing but a pen and paper, it would have been used instead of the heavyweight tables :-) It's not by luck or magic they were so widespread before the appearance of calculators.

(too long for a comment)
@Nick There is something else I didn't read at first: "free myself from log tables and calculators which are not at my disposal during exams". An exam without any computing tool that would ask computations would be... strange. But not unbelievable, as I saw more or less this in France at the chemistry test in competitive examinations at the end of classes préparatoires. IIRC, only a tiny (1/4 of a sheet) table of logarithms was given to compute numerical results. Believe it or not, some schools still allow slide rules for these exams (and only a couple of years ago, also tables of logarithms, I mean, the "real" ones, not the one sheet ersatz). Two examples I know of are the Mines-Ponts exam, and the École Polytechnique: it's still explicitly stated in the exam rules as of 2014 exams. However, virtually no student is coming to the exam with a slide rule, and I bet only few would know what it is, let alone how to use it appropriately.
A: Although this is not exactly what you ask for, if you have a calculator with square root, you can use the same method Briggs used in 1620 (before calculus, integration, and power series).   Take the square root of your number repeatedly until you get a 1 followed by some zeros and a set of digits.  Stop when the number of zeros and the number of digits are about the same.  Subtract the 1 and multiply by the appropriate power of 2 (the number of times you hit square root), and you are done.  Keep in mind that for Briggs, extraction of square root was a tedious affair; for you, it is a single finger poke.  
The bad news is that you will have to memorize a constant to convert this natural log to base 10.   But you only have to memorize half of it because it is 0.4343.  I used this method in 1973 when an engineer at work got a box of defective five banger calculators.  He fixed them by cleaning the key contacts and sold them for $3.   I needed the more precise logs than a slide rule provided for decibel calculations.
There are refinements that have been touched on by others here, such as 2(x-1)/(x+1), but that doesn't address your problem of working by hand.  
I recommend that you memorize the above constant, Log(e), and also the logs of 2 and 3.  I assume that you have already memorized the log of 10 to one billion decimal places.  From these factors, you can construct a number that is close to your target.  But this gets to be more work than the simple division problem you need to address.
For crude work, I memorized the numbers whose logarithms are 0.1, 0.2, etc., which are the power ratios for 1, 2, etc. decibels.  Eyeball interpolation gets me the second digit of the log.  Not as good as a slide rule or the above square root method, but better than nothing when many calculations must be chained.   I am presently building a slide rule with a spiral scale 50 turns around a 2" pipe, inspired by the Otis King calculator.  It is easy with a Microsoft excel chart.  I think it would give you the four digits you seek, but it is not a portable device.
