$g(x) = \displaystyle\frac{x + 1}{(x + 2)^{10}}$
by the quotient rule I get
$ \begin{align} g'(x) & = \displaystyle\frac{1.(x + 2)^{10} - 10.1.(x + 2)^9(x + 1)}{(x + 2)^{20}}\\ & = \displaystyle\frac{x + 2}{(x + 2)^{11}} - \frac{10.(x + 1)}{(x + 2)^{11}} \\ & = \displaystyle\frac{-9x - 8}{(x + 2)^{11}} \end{align} $
my handbook however gives the answer as
$\displaystyle\frac{1 - 9x}{(x + 2)^{11}}$
I just can't see where I made a mistake