Subgroups of the Klein-4 Group Can anyone explain to me the subgroups of the Klein-4 group? I'm trying to view it this way:
I want some groups that are not empty and $ab^{-1} \in H$, where $H$ denotes the subgroups I am looking for.
So the Klein-4 group is as follows: $V_4 = \langle a,b : a^2 = b^2 = (ab)^2 = 1\rangle $. I'm a bit confused by the $\langle $ and $\rangle $ to denote a cyclic group but I sort of follow what's going on.
I guess the group itself and the trivial subgroup are there...But can you explain to me how to find the rest?
Possible answer:
Trivial subgoups $ \{\ e \}\ $ has order one.
Order 2: $\{\ e,a \}\ , \{\ e,b \}\ , \{\ e,ab \}\ $
Order 4: The group itself. As the order of the subgroups must divide the order of the group, these must be all the subgroups.
 A: Hints:
Lagrange's theorem says the only possible sizes of subgroups and orders of elements are $1,2,4$.
The identity element is one of the elements in each of the subgroups, and each element of order $2$ generates a subgroup of order $2$. Are there any elements of order $4$? By thinking about these ideas, you should see how to come up with your list.
The notation $\langle a,b,c,\ldots\mid\ldots \rangle$ is a special one for describing a presentation of a group. It is related to set notation but is not exactly the same. 
The letters in the left half denote the supply of symbols that generate the group. Multiplying these symbols just involves using exponents and writing symbols next to each other. For example, $a\cdot b=ab$, $ab\cdot b=ab^2$ and so on. So don't get me wrong: the left half isn't a complete list of what's in the group, it's a list of symbols that generate the group. 
The equations in the right half are rules that control the behavor of the multiplication. For example in the Klein $4$ group, one of the rules is that $b^2=1$, so in fact $ab\cdot b=ab^2=a1=a$. These are called relations for this group, since they relate products to each other and control the group operation.
A: $G=\{e,a,b,ab\}$ the relation says that every nontrivial element has order $2$.
Thus,$H_1=\{e,a\}$,$H_2=\{e,b\}$,$H_3=\{e,ab\}$,$H_4=\{e\}$,$H_5=G$ are all subgroups.
The notation $<x,y,z..>$ means that group is generated by elements $x,y,z..$ if a group is generated by one elements then it is cylic.In that case, $G=<a,b>$ means every element of $G$ can be written in terms of $a$ and $b$ satisfying the given relation.
