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Three cards are drawn at random(without replacement) from an ordinary deck of 52 cards. Find the number of ways in which one can draw a. A diamond and a club and a heart in succession b. Two hearts and then a club or spade

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  • $\begingroup$ a) The first can be any of $13$ cards. For each choice of first card, there are $13$ choices for second card (and so on). b) This first can be any of $13$ cards. For each choice of first card, there are $12$ choices for second card. And for each choice of first and second, there are $13$ choices for the third card. And so on. $\endgroup$ – André Nicolas Mar 3 '14 at 0:02
  • $\begingroup$ @ André Nicolas So this will be the equation i guess, for a, 13X13X13. For b, 13X12X13. Am i right? I'm kinda confused. Sorry. $\endgroup$ – Omni- Mar 3 '14 at 0:07
  • $\begingroup$ For b) it is $(13)(12)(13)(13)$. You have a) right. $\endgroup$ – André Nicolas Mar 3 '14 at 0:08
  • $\begingroup$ You are welcome. $\endgroup$ – André Nicolas Mar 3 '14 at 0:18

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