# Holomorphic bounded function with zeros in $1-1/n$

The question is:

Let $f$ be holomorphic function in unit disc, which is bounded and have zeros in points $1-1/n$ for natural $n$. Then $f$ is equal to zero.

Identity theorem does not help because point 1 is not inside unit disc. I suppose it follows from the fact that any holomorphic function in unit disc is either unbounded or may be extended on larger disc, but I can not prove it. Is it correct?

• There are bounded holomorphic functions on the unit disk that cannot be extended to a larger disk. Any bounded holomorphic function with infinitely many zeros in the disk that is $\not\equiv 0$ for example. Feb 13 '14 at 15:39
• This is an application of the identity theorem.
– user21467
Feb 13 '14 at 16:09
• But limit point is 1, which is not inside of unit disc Feb 13 '14 at 16:15
• Oh, I see. Yes, I read too quickly.
– user21467
Feb 13 '14 at 17:21

This follows from Blaschke's condition: the sequence $(a_n)$ is the zero sequence of a bounded holomorphic function on the unit disc if and only if
$$\sum_n (1-|a_n|) < \infty.$$
As noted, this doesn't follow from the identity theorem: there are unbounded holomorphic functions on the unit disc whose zero sequence is $(1-1/n)$.