# Mechanics-Maths

Particles $A$ and $B$ are moving along horizontal straight lines which lie in the west east direction. At a certain time, $A$ passes a point $P$ moving to the east with speed $5$ ms$^{-1}$ and constant acceleration $1$ ms$^{-2}$. Simultaneously, $B$ passes a point $Q$ east of $P$ with speed $4$ ms$^{-1}$ towards the west but with constant acceleration $2$ ms$^{-2}$ towards the east. Given that the distance $PQ$ is $28$ m, Calculate

a) The distance of $A$ from $P$ when $B$ reverse direction

b) The time taken after the start for $A$ to overtake

c) The further time taken for $B$ to overtake $A$

• Please show us what u have done.. – Apurv Feb 10 '14 at 12:37
• i posted the question because i cant figure out any of a,b and c – Abdel Moniem Feb 10 '14 at 12:47
• add whatever u have done, to the question... Questions with no efforts get downvoted. – Apurv Feb 10 '14 at 12:48
• Could you also help and i will try my best – Abdel Moniem Feb 10 '14 at 12:56
• v=u+at v=0 as B has reversed so 0=4-2t so t=2 seconds s=5(2)+1/2(2)^2=12 – Abdel Moniem Feb 10 '14 at 13:05