# PROVE if $x \ge-1$then $(1+x)^n \ge 1+nx$ , Every $n \ge 1$

Use mathematical induction to prove this. Here is my answer but I stuck at certain point.

Base Case: n=1 $$(1+x)^1 \ge 1+x$$ True ,

Induction Case: n=k assume $$(1+x)^k \ge 1+kx$$ n=k+1 $$(1+x)^k+1 \ge 1+(k+1)x$$ $$(1+x)^k *(1+x) \ge 1+ kx+ x$$

      Stuck!!!

• Please, fix your post. You didn't write what you want to prove. Also, you can use math-mode to write mathematics in your post, like $(1+x)^k$. – frabala Feb 10 '14 at 2:05
• how to access math mode, how can I write, I am new – hacikho Feb 10 '14 at 2:06
• Here: math.stackexchange.com/editing-help#latex . You use the dollar signs. – frabala Feb 10 '14 at 2:09
• thank for showing me how to edit my question – hacikho Feb 10 '14 at 2:25