I am stumped on a problem with two parts. First part I think I might have done correctly, Second part im lost
From a group of 4 women and 6 men, In how many ways a committee consisting of 2 women and 3 men can be formed.
a) without any restrictions
b) if a one particular woman is not eligible to be on the committee
a) This one I think I understood. I had to find the possible combinations of the men and women and multiply them right? So $^4C_2.^6C_3$
b) I'm totally stuck on this one...