# relationship between commutative matrix's eigenvalues

i am interested if there is some relationship between eigenvalues of commutative matrices?or for any two matrix $A$ and $B$,we have following equation

$A*B=B*A$

for example

A=[1 2;3 4]

A =

1     2
3     4


and second matrix

B=[7 10; 15 22]

B =

7    10
15    22


we have

A*B

ans =

37    54
81   118


and

B*A

ans =

37    54
81   118


now i have several questions,just in simple please help me to clarify it,what is relationship between eigenvalues of $A$ and $B$?or between $A*B$ and $A$?or between product of these two matrix and matrix $B$?as i know for some given two matrices

$e^{A+B}=e^{A}*e^{B}$

when $A*B=B*A$

because we can represent matrix exponential for diagonalisable matrix using eigenvalues,can we see some relationship between commute matrices?thanks in advance

This is because commuting set of matrices are simultaneously trianguralizable. The eigenvalues of an upper triangular matrix are the diagonal elements. Eigenvalues of $AB$ are just the product of eigenvalues of $A$ with those of $B$.
• Non zero eigenvalues are the same for $AB$ and $BA$. The eigenvalues are the products of eigenvalues of $A$ and $B$. For example if $A$ has an eigenvalue 2, and $B$ has an eigenvalue $4$, then $AB$ has an eigenvalue $8$, and so on. Hope that helps. – voldemort Feb 1 '14 at 18:25
• Yes :). Even more is true. If $P,Q$ are polynomials, and $AB=BA$ then $P(A)Q(B)=Q(B)P(A)$. – voldemort Feb 1 '14 at 18:30