Take for example the set $X=\{a, b\}$. I don't see $\emptyset$ anywhere in $X$, so how can it be a subset?
4 Answers
Because every single element of $\emptyset$ is also an element of $X$. Or can you name an element of $\emptyset$ that is not an element of $X$?
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$\begingroup$ But there are no elements in ∅, so how can every single element of ∅ be an element of X? You ask if we can name an element of ∅ that is not an element of X-- the answer is I can't, but conversely you can't name a single element of ∅ that IS an element of X. So how can we derive such a conclusion that the empty set is a subset of every set? It seems to me that the quality of being a sub-set cannot apply in this scenario because the definition assumes the existence of at least one element inside the set $\endgroup$ Apr 27, 2022 at 18:51
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that's because there are statements that are vacuously true. $Y\subseteq X$ means for all $y\in Y$, we have $y\in X$. Now is it true that for all $y\in \emptyset $, we have $y\in X$? Yes, the statement is vacuously true, since you can't pick any $y\in\emptyset$.
You must start from the definition :
$Y \subseteq X$ iff $\forall x (x \in Y \rightarrow x \in X)$.
Then you "check" this definition with $\emptyset$ in place of $Y$ :
$\emptyset \subseteq X$ iff $\forall x (x \in \emptyset \rightarrow x \in X)$.
Now you must use the truth-table definition of $\rightarrow$ ; you have that :
"if $p$ is false, then $p \rightarrow q$ is true", for $q$ whatever;
so, due to the fact that :
$x \in \emptyset$
is not true, for every $x$, the above truth-definition of $\rightarrow$ gives us that :
"for all $x$, $x \in \emptyset \rightarrow x \in X$ is true", for $X$ whatever.
This is the reason why the emptyset ($\emptyset$) is a subset of every set $X$.
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1$\begingroup$ Shouldn't the last implication be "$\text{for all x, }x \in \emptyset \rightarrow x \in X$ is true" $\endgroup$– maunaJun 30, 2014 at 13:20
Subsets are not necessarily elements. The elements of $\{a,b\}$ are $a$ and $b$. But $\in$ and $\subseteq$ are different things.
Or Can you name an element of ∅ that is not an element of X?
. If you think it like this, given ∅ and X, you can't really find an element of ∅ (nothing) that you don't find in X, and as a subset A is a just a set whose elements (every element) are included in another set B, that is you can't find an element in A which is not in B, it makes more sense. $\endgroup$