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This question already has an answer here:

Somebody explained me this problem, but I am not sure to understand what is wrong.

Three people go to a bar to have a drink.
To pay the bill everyone gives $10.
The barman gives back $5 coins.
Every people take $1 back and leave the $2 other dollar for the barman.

If everybody give \$10 and get \$1 back, they paid \$9 right?

3 * $9 + $2 = $29

Where is the missing dollar?

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marked as duplicate by Jyrki Lahtonen Oct 13 '16 at 8:56

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

  • $\begingroup$ if every people take $1$,then barman also take $1$ right? :D $\endgroup$ – dato datuashvili Jan 29 '14 at 15:17
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    $\begingroup$ Dat grammar wow $\endgroup$ – qwr Jan 29 '14 at 17:10
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    $\begingroup$ You are adding the 2 the barman got to the 27 they spent. The 2 comes out of the 27 to get the 25 the bar got. There is no reason to get anything sensible when you add 27 and 2 here. $\endgroup$ – Ross Millikan Jan 29 '14 at 17:10
  • $\begingroup$ @qwr I eventually fixed it but you could also have proposed to edit the question yourself. Tell me if you see something I missed. $\endgroup$ – Natim Dec 30 '17 at 16:28
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True $3*9=27$.

But they paid $25\$$ and gave $2 \$ $ tip. And

$$25+2=27=3*9 \,.$$

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  • $\begingroup$ Of course. Thanks. $\endgroup$ – Natim Jan 29 '14 at 17:43
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There is no missing dollar.

\$30 - \$5 = \$25 paid to the barman. \$2 tip + $3*\$1$ = remaining \$5.

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The math is simples:

  1. 10*3 = 30 and 30-25 = 5
  2. (1*3)+2= 5

There is no loss.

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