The relation is neither transitive nor reflexive. It is only symmetric.
Remember that the condition for transitivity is that if $a \sim b$ and $b \sim c$, then $a \sim c$.
We have $1 \sim 2$ and $2 \sim 1$. If transitivity held, we would expect $1 \sim 1$ and $2 \sim 2$. But our relation does not contain $(1,1)$ or $(2,2)$ so it is not transitive.
The relation is also obviously not reflexive, because it does not contain $(1,1)$ and $(2,2)$.
Moreover, note that transitivity does not necessarily imply reflexivity: consider $\{(a,b),(b,c),(a,c)\}$ which is transitive, but neither reflexive nor symmetric. (However, a relation that is both transitive and symmetric will be reflexive: I'll leave proving this fact to you ask an exercise.)