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This question already has an answer here:

I know I should use the triangle inequality.

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marked as duplicate by user61527, Dan Rust, Lost1, Micah, Jack D'Aurizio Jan 25 '14 at 20:15

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

  • $\begingroup$ Can it be done in another way? $\endgroup$ – grayQuant Jan 25 '14 at 19:26
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Hint: $|a|=|(a-b)+b|\le|a-b|+|b|$. Then switch the roles of $a$ and $b$.

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