Tips for solving linear equations Is there an easier way to solve linear equations than trial and error?
$$2(3b -1) - (4b -6) = 3$$
 A: $2(3b-1)-(4b-6)=3$
$6b-2-4b+6=3$
$2b+4=3$
$2b=-1$
$b=-\frac12$
A: Use the distributive principle to write $2(3b-1)=6b-2$
Now gather all the terms in $b$ together and put all the terms without $b$ on the right.
 Divide by the coefficient of $b$.
A: Given the equation: 
$$2(3b -1) - (4b -6) = 3$$
We must expand first, note the minus sign is distributed just like the $2$:
$$2(3b -1) - (4b -6) = 3$$
$$6b-2+ (-4b+6) = 3$$
$$6b-2-4b+6 = 3$$
Gathering like terms and solving for $b$:
$$2b=-1$$
$$\boxed{b=\dfrac{-1}{2}}$$
A: To solve $2(3b - 1) -(4b -6) =3$ for the unknown $ b $, it is best to simplify the equation's left side. To do that:


*

*Distribute: $2(3b - 1) -(4b -6) = (2 \cdot 3b - 2 \cdot 1) - 1 \cdot 4b - 1 \cdot {-6} = 6b - 2 - 4b + 6$


*Combine like terms: $ 6b - 2 - 4b + 6 = 6b - 4b - 2 + 6 = 2b + 4 $
Thus, $$ 2(3b - 1) -(4b -6) =3 $$ $$ <=> 2b + 4 = 3$$
Subtract $4$ from each side of the equation:
$$ 2b + 4 - 4 = 3 - 4$$ $$<=>2b = -1$$
Finally divide $2$ to each side to isolate the unknown $b$:
$$\frac{2b}{2} = \frac{-1}{2}$$ $$<=>b = -\frac{1}{2}$$
Thus, $ b = -\frac{1}{2} $.
