I had to integrate an area delimited by a quarter of a circle, something like this:
Which comes from the equation:
$$x^2 + (y-10)^2 = 8^2$$
I wondered if it was possible to express the same curve but using sin instead?
I read somewhere (cannot find it again) you could use something like:
$$y = 10 - 8∗\cos(xπ/(2∗8))$$
But it seems just wrong? Can you confirm that it's not possible to do a perfectly circle-shaped form using sin/cos using "classic" equations (not parametric equations).
I'm not interested in polar coordinates either... I want to know if it's possible to have a final equation in the form of:
$$y = A + B * \sin(C * x)$$ for some values of A/B/C. You are free to add some cos() in there :)
Apparently the question I should have asked is: "Is it possible to express parts of a circle as a cartesian equation involving sin/cos"