How can I express the equation

$c = 2^{m+1} - 2^m$

in terms of m? t.i.a.

  • $\begingroup$ It already seems to be expressed in terms of $m$. Please clarify what you want. $\endgroup$ – Henning Makholm Sep 14 '11 at 22:11

What do you means by write in term of $m$? Do you means simplify? Do you mean any of the following?

$c = 2^{m}(2 - 1) = 2^{m}(1) = 2^m$

or $m = log_2 c$.

  • $\begingroup$ If you are asking the OP for clarification, please do so in the comments. $\endgroup$ – Austin Mohr Sep 14 '11 at 22:09
  • $\begingroup$ I'd be surprised if OP meant anything other than "solve for $m$ in terms of $c$," and in that context this qualifies as an answer. $\endgroup$ – Gerry Myerson Sep 14 '11 at 22:28

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