I am trying to put the following expression $x^2 + 6x + 7$ in the form $(x + r)^2 + s$ so I can complete the square.
I understand the first couple of steps,
$(x^2 + 6x + 7)$
$b =\left(\frac62\right)^2 = 9$
$x^2 + 6x + 9 - 9 + 7$
$(x^2 + 6x + 9) - 9 + 7$
$(x^2 + 6x + 9) - 2$
From this point on I'm not sure what to do to put it in $(x + r)^2 $. What is $r?$ Any help is much appreciated.
Also, I have one question last important question:
1) Will this method work for any expression / equation in solving the square?