The sum of areas of 2 squares is 400and the difference between their perimeters is 16cm. Find the sides of both squares.
I HAVE TRIED IT AS BELOW BUT ANSWER IS NOT CORRECT.......CHECK - HELP!
Let side of 1st square=x cm.
∴ Area of 1st square=x²cm²
GIVEN, Sum of areas =400cm²
∴ Area of 2nd square=(400-x²)cm²
AND side of 2nd square=√[(20-x)² i.e.20-x .......(1)
Difference of perimeters=16cm.
4x-4(20-x)=16 (ASSUMING THAT 1ST SQUARE HAS LARGER SIDE)
HENCE - SIDE OF 1ST SQUARE = 12CM ;
SIDE OF 2ND SQUARE=20-12=8CM. [FROM (1)]
WHICH IS NOT THE REQUIRED ANSWER AS SUM OF AREAS OF SQUARES OF FOUNDED SIDES IS NOT 400CM²