Suppose that the probability for an applicant to get a job offer after an interview is 0.01. An applicant plans to keep trying out for more interviews until she gets offered. Assume outcomes of interviews are independent. What is the probability she will need to attend more than 2 interviews?

My Solution :


Let X denote the number of interviews to be attended.

so, Pr(X>=3)=(1-.01)^2=.98

This question is off a textbook and the given answer is 0.81. Could someone please advice on the correct solution, and thanks

  • $\begingroup$ The data 0.01 is probably 0.1. $\endgroup$
    – Did
    Jan 7 '14 at 18:37
  • $\begingroup$ Yeah that seems to work. Must be misprinted. Thanks. $\endgroup$ Jan 7 '14 at 18:40

The data 0.01 is probably 0.1.


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