I have been given this equation for homework and I don't know how to solve it.
$y=\dfrac{\ln\left(\dfrac{x}{m}-sa\right)}{r^2}$
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$\begingroup$ reddit.com/r/math/comments/1tbh9o/… and its link imgur.com/uMHc7I3 $\endgroup$– user61527Commented Dec 26, 2013 at 20:49
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1$\begingroup$ mathematical "merry x-mas" $\ddot \smile$ $\endgroup$– K. RmthCommented Dec 26, 2013 at 20:51
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1 Answer
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$y=\dfrac{\ln\left(\dfrac{x}{m}-sa\right)}{r^2}$
$y=\dfrac{\ln\left(\dfrac{x}{m}-as\right)}{r^2}$ , then we have
$r^2y=\ln\left(\dfrac{x}{m}-as\right)$
$e^{r^2y}=\dfrac{x}{m}-as$
$me^{r^2y}=x-mas$
$me^{rry}=x-mas$
