Rewrite the iterated integral $$\int_0^1 \int_0^{\sqrt{2y - y^2}} (1 - x^2 - y^2)\,dx\,dy$$ in polar coordinate form. Do not evaluate the integral.
Here is my answer:
$$\int_0^\pi\int_0^{2sin\theta}(1-r^2)rdrd\theta$$
I evaluated both double integrals using Wolfram Alpha and it seems my answer is wrong.