Here is the question....enter image description here

When I put it into wolfram to just get a good visual of it...it looks like this... enter image description here

I believe this is the formula we use enter image description here

The problem is, I don't quite understand what they are asking for? Are they saying that they want the area of those two identical regions that range horizontally from 0-pi and from -2pi to -pi. and vertically from around 12-15? Not sure how to find the area for that. That would be cool if you go do the area of one side from -2pi to pi and then to the area of the other side from 0 to pi. That does not seem to be the correct way to do it though?

Let me know what you guys think!

Thanks to all who help!

  • 1
    $\begingroup$ You need to plot these in polar coordinates. Then you will get two closed curves, and thus the meaning of "inside" and "outside" should become clear. $\endgroup$ – Carl Love Dec 8 '13 at 3:45

This is the plot that you need.enter image description here

Maple code:

plot( [6*sin(t)+6, 18*sin(t)], t= 0..2*Pi, coords= polar, legend= [6*sin(t)+6, 18*sin(t)], scaling= constrained );

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  • $\begingroup$ How did you get that?? @CarlLove $\endgroup$ – Christopher23 Dec 8 '13 at 3:52
  • $\begingroup$ Maple. It's math software---the main competitor of Wolfram's Mathematica. $\endgroup$ – Carl Love Dec 8 '13 at 3:56

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