So here is my problem:
Find an integral for the area of the surface generated by revolving the curve $y=sin(x)$ between $0 \le x \le \pi$, about the x-axis
Just thinking about the problem I feel like I would just do the following:
$$2\int_{0}^{\pi}\sin(x)\mathrm{d}x$$
But I'm not sure if this is the way to go about doing this. Any hints?
\sin
instead ofsin
and write $\mathrm dx$ using\mathrm{d}x
instead ofdx
. $\endgroup$