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I've just learned about the idea of local ring, but the only concrete examples in the book are $\{p/q \in \mathbb{Q} \mid q \mbox{ odd}\}$ and the power series ring $k[[x]]$ for some field $k$. But the only prime ideals they have are just $\{0\}$ and their maximal ideal.
Can anybody provide me with more concrete examples of local rings with "non-trivial" prime ideals?
First consider the polynomial ring $R=F[x,y]$ for a field $F$. One chain of prime ideals in this ring is $(0)\subseteq (x)\subseteq (x,y)$. Now $(x,y)$ is a maximal ideal, but there are other maximal ideals, for example $(x+1,y)$.
The easiest way to eliminate the other maximal ideals is to pass to the localization at the prime $M=(x,y)$ so that the new ring $R_M$ is a local ring. It is a property of localization that the prime ideals contained in $M$ will have prime counterparts in $R_M$, with the same containment relations and everything. Thus the chain $(0)_M\subseteq (x)_M\subseteq (x,y)_M$ will be a properly ascending chain of prime ideals in the new ring $R_M$.
Even if you are not handy with localization now, you probably will need to be soon, so trying to understand this type of example is worthwhile.
If $k$ is any field then the ring of formal power series in two variables $k[[x,y]]$ is a local ring with "non-trivial" prime ideal $(y)$ since $k[[x,y]]/(y)\cong k[[x]]$.
More generally: $k[[x_1,...,x_n]]$ is a local ring with maximal ideal $(x_1,...,x_n)$ and prime ideals $(x_{i_1},...,x_{i_m}),\,1\le i_1 < \cdots i_m \le n$.
You will soon learn about localization and that will provide many many examples.
An example: Let $R$ be the ring of rational functions $f/g\in\mathbb Q(x,y)$ such that, when expressed in irreducible terms, the denominator is not divisible by $x$.
