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Dear all, I need help to simplify this Boolean algebra. Please give me a answer step by step. Thanks


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Coming to the solution:

$(abc + ab'c + a'bc +a'b'c+a'bc'+abc')$

$=c[ab + ab'+ a'b + a'b'] + c'[a'b+ab]$

$=c[1] + c'[b(a+a')]$

$=c + c'b$

$=c + b (absorption law).

This is what you need

  • $\begingroup$ Just mark the answer as correct if it correct, or vote up if the answer is useful. No need to say thanks. $\endgroup$ – sai kiran grandhi Nov 27 '13 at 6:12
  • $\begingroup$ The c' term is redundant because of c, so = c + b is the final answer. $\endgroup$ – StainlessSteelRat Sep 8 '16 at 16:23

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