I was asked to evaluate the following using Simpson's rule (by using 2 strips). Below is the function and my answer to it. What am I doing wrong?
$$\begin{align} \color{red}{\int_1^{1.6}\dfrac{\sin2t}{t}\,\mathrm dt} & \color{blue}{=\int_1^{1.6}\dfrac{\cos2t^2-\sin2t}{t^2}=\dfrac{0.6}2\big[f(1)+4(1.3)+f(3)\big]} \\\,\\ &\color{blue}{=\big[-1.32-5.1+0.6\big]} \end{align}$$
When I plugged in the values I put my calculator in Radian mode but the answer I get is negative. The correct answer is 0.2460
Thank you.