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A circle is inscribed into the rhombus ABCD with one angle 60. The distance from the centre of the circle to the narest vertex is equal to 1. If P is any point of the circle ,then $$(PA)^2 + (PB)^2 +(PC)^2 + (PD)^2$$ is equal to?
Required, but never shown
5 years, 8 months ago