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The question is: A card is drawn from an ordinary pack(52 cards) and a gambler bets that either a spade or an ace is going to appear. The probability of his winning are? I think the answer is $\frac{16}{52} = \frac{4}{13}$. Did I go "probably" go wrong somewhere?

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  • $\begingroup$ probably not wrong $\endgroup$ – Henry Nov 5 '13 at 15:48
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There are 16 `good' cards (the 13 spades and the three other aces), out of 52 total, so you're correct.

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Nope, you're correct! (Converting this to an answer.)

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  • $\begingroup$ Beaten by a few seconds by Cheyne H! $\endgroup$ – Ahaan S. Rungta Nov 5 '13 at 15:49
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There are 13 spades that contain one ace and there are remaining three aces, thus there are altogether 16 choices for the bet and the probability = 16/52 and you are correct.

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