Find the cusps for the congruence subgroup $\Gamma_0(p)$. How does one go about doing this? I know the definition of a cusp - the orbit for the action of $G$, in this case $\Gamma_0(p)$, on $\mathbb Q\cup\{\infty\}$, but I don't see how to get myself started thought.

The solution is "the classes of $0$ and $\infty$".

  • $\begingroup$ Do you know what the cusps are for the full group SL2Z? $\endgroup$ – David Loeffler Oct 31 '13 at 7:45
  • $\begingroup$ They are $i,\rho,\rho^2,\infty$? $\endgroup$ – Haikal Yeo Nov 2 '13 at 19:21
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    $\begingroup$ $\infty$ is the only cusp in the case of $SL_2(\mathbb{Z})$, the other points you mention are elliptic points, rather than cusps. $\endgroup$ – user27126 Nov 3 '13 at 1:40

first of all, you can try to see who is in the orbit of $\infty$.

If $z$ is in the orbit of $\infty$ then there exist a matrix on $\Gamma_0(p)$ say $\gamma=\left(\begin{matrix} a & b \\ pc & d\end{matrix}\right)$ such that $\gamma \infty =z$. This implies $\frac{a}{pc}=z$, then the numbers in the orbit of infinity are the rational number of the form $\frac{a}{pc}$ where $\gcd(a,pc)=1$ and $a\neq 0$ (because $ad-pbc=1$) .

On the other hand, it is easy to check that the other rational numbers are in the same orbit, and that $0$ is in that orbit.


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