Find the area bounded by
$$ f(x) = x + 6 $$ $$ g(x) = x^3 $$ $$ h(x) = -\frac{x}{2} $$
Edit Fixed simple error on h(x)
I already drew the grew, although it is very hard to really tell where they seem to intersect.
It looks like on the left side of the graph f(x) intersects with h(x) at -12. However going toward the right side of the graph it looks like I'll have to integrate base on f(x) and g(x).
I'm thinking this is a two part integration problem, but I'm unsure of what my bounds should be.