Explain the Absorption Law I am currently in a Discrete Math class and reviewing some of my terminology and I don't really understand the Absorption Law. I am not looking for a proof or a truth table but an explanation in layman's terms.
Absorption Law
$$
A ∨ (A ∧ B) = A
$$
$$
A ∧ (A ∨ B) = A
$$
$$
A ∪ (A ∩ B) = A
$$
$$
A ∩ (A ∪ B) = A
$$
 A: For the first one, either $A$ is true, or both $A$ AND $B$ are true.  In either case, $A$ is true.  On the other hand, if $A$ is true, then the first is true so the expression is true.
The others are similar.
A: $A\vee (A\wedge B) \\ = (A\wedge T) \vee (A \wedge B) \\= A \wedge (T \vee B) \\= A \wedge T \\= A$
Note : in the third line i used the inverse of distributive law
A: As per logic perspective, we think values either as TRUE or FALSE, I.e: 0 or 1.
So here we can assume 0 or 1 only, for A and B respectively. 
So consider A=1 and B=0,
Now put the values in asking law,
LHS=A.(A+B)
        =1.(1+0)
        =1.(1)
        =1=A   ...[because A=1]
            =RHS
Now you are thinking, why I cannot take value of B=1 and A=0,
Yes!!  You are independent to that,
If you take A=0 then multiply with adjacent terms in bracket, your whole answer will be zero, again, lhs will be equal to rhs.
So you will get answer as the value of A in every attempt.
Now for A+(A.B)=A
If A=1, B=0
Put,      1+(1.0)=1   [A=1]
Or if A=0, B=1
Then,
        A+(A.B)=A
        0+(0.1)=0     [A=0]
Hence you will get answer as A alwasy!!!!
