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A rotational surface area is created when a curve in the $xz$-plane, with parameterization $\def\i{\pmb{i}}\def\k{\pmb k}$ $r=x(t)\i + z(t)\k$ , $t \in [a,b]$, rotates around the $z$-axis. This surface is parameterized by;

$$t \mapsto \bigl( x(t)\cos\theta, x(t)\sin\theta, z(t)\bigr)^t $$

$t \in [a,b]$, $\theta \in [0,2\pi)$.
Use the above information to parameterize the torus that is created when a circle $(x-3)^2+z^2=4$ rotates around the $z$-axis.

The above is the first of a number of exercises on parametric surfaces which I will attempt to complete. I have not recieved any solved examples or specific guidance on the subject so I am hoping that someone here could show me how this is done.

I apologize for any spelling errors and the general lack of LaTeX.

Help is much appreciated!

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So we have to parametrize the given circle $(x-3)^2 + z^2 = 4$, in the form $\def\i{\pmb i}\def\k{\pmb k}$$$r(t) = x(t)\i + z(t) \k $$ on some $t$-intervall $[a,b]$, then we can apply the given information. Keeping in mind, the construction of sine and cosine, we have that $(\cos t, \sin t)$ describes a circle of radius 1 around $0$, we have a circle of radius $2 = \sqrt 4$ around $(3,0)$, now $(2\cos t, 2\sin t)$ is a circle of radius 2 around $0$, adding $(3,0)$ we are done and obtain $$ r(t) = (3 + 2\cos t)\i + 2\sin t \;\k, \qquad t \in [0,2\pi] $$ for the given circle. Now apply the given information.

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  • $\begingroup$ So I get: x(t,θ) = (8 + 2 cos t) cos θ, y(t,θ) = (8 + 2 cos t) sin θ and z(t,θ) = 2 sin t? Is there a way to include a picture? I have drawn the figuere in MATLAB and would like to check if it is accurate. $\endgroup$ – Soakr Oct 15 '13 at 14:45
  • $\begingroup$ @Soakr: Looks fine. $\endgroup$ – martini Oct 15 '13 at 14:49

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