This was a question that came up at work, and we ended up with several different answers!
In the game, there are two teams of four, and each person gets a randomly assigned number from one to eight. This is done by picking the numbers out of a bag.
The question is: if the order of people within the team doesn't matter - that is, if the team draws 1,2,5,8 or 8,2,5,1 it's the same - then what are the odds of either team drawing 1,2,3,4 or 5,6,7,8?
My answer was that if one team gets either of those groups, the other team will always have the other group, so the fact that there are two teams doesn't matter. Thus, it comes down to: what's the chance of a team picking [1,2,3,4] or [5,6,7,8], and I make that 1/35.
Am I correct? Does it make any difference how the numbers are drawn - for example, if one team draws four and then the other does, or if they draw alternately?