Here's the problem again:
Use a proof by contradiction to prove the following universal statement:
If $x$ is a real number and $x^2 + x - 2 = 0$, then $x \neq 0$
Here's my attempt at it:
- Let $p$ be "$x^2 + x - 2 = 0$" and $q$ be "$x \neq 0$".
- Assume that $x^2 + x - 2 = 0$ and assume $x = 0$.
- (This is where I got stuck)
I'm not sure how to proceed, I've worked with statements like, "If $3n+2$ is odd, then $n$ is odd" but I've never worked with equations like this. How would I proceed with this proof by contradiction?