Let the domain be the set of all non-negative integers, $\mathbb N = \{0, 1, 2, \ldots\}$.
Let $P(m,n)$ denote "$n \geq m$".
$∃n\,∀m\,P(m,n):$ "There exists an $n \in \mathbb N$ such that for every $m \in n,\;n \geq m$." Is there any particular non-negative integer(s) $n$ that is/are greater than all other such integers? NO. There is no "greatest integer". Suppose such $n$ existed. But we still have that $p = n+1 \gt n$, etc.
$∀m\,∃n\,P(m,n)$ Now this statement expresses the following: "For every integer $m \in \mathbb N,\;$ there is some integer $n\in \mathbb N$ such that $n \geq m$. This is true. Whatever $m$ we choose, there exists an integer $n$ (for example, $n = m+1$) such that $n \geq m.$
Key note: It is crucial here to note how the order of the quantifiers significantly changes the meaning of the statement!