If we try to divide any two random arbitrarily long rational numbers like




Is it guaranteed that the result is also a rational number?

  • $\begingroup$ But if we divide arbitrary amount of rational numbers then it's possible to get an irrational one :) But of course it's not what you are asking. $\endgroup$ – Mihail Aug 5 '15 at 16:09

The quotient of two rationals is always a rational.

For if $\alpha = \frac{a}{b}$ and $\beta = \frac{c}{d}$ with $a, b, c, d$ integers with none of $b, c, d$ being zero, then

$$\frac{\alpha}{\beta} = \frac{ad}{bc}$$

is a quotient of integers, and so is rational.

  • $\begingroup$ There is a mistake: the last equation should read $\frac{\alpha}{\beta} = \frac{ad}{bc}$. $\endgroup$ – jub0bs Apr 8 '14 at 16:17

If we get an irrational number by dividing a rational number by another rational number, then product of rationals won't be a binary operation in $\mathbb{Q}$. But we know that $\mathbb{Q}\setminus \{0\}$ is a group with respect to multiplication.


protected by Community Aug 13 '15 at 23:16

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