# Can we ever get an irrational number by dividing two rational numbers?

If we try to divide any two random arbitrarily long rational numbers like

103850.2387209375029375092730958297836958623986868349693868398659825528365...


and

127.123123123...


Is it guaranteed that the result is also a rational number?

• But if we divide arbitrary amount of rational numbers then it's possible to get an irrational one :) But of course it's not what you are asking. Aug 5, 2015 at 16:09

For if $\alpha = \frac{a}{b}$ and $\beta = \frac{c}{d}$ with $a, b, c, d$ integers with none of $b, c, d$ being zero, then
$$\frac{\alpha}{\beta} = \frac{ad}{bc}$$
• There is a mistake: the last equation should read $\frac{\alpha}{\beta} = \frac{ad}{bc}$. Apr 8, 2014 at 16:17
If we get an irrational number by dividing a rational number by another rational number, then product of rationals won't be a binary operation in $\mathbb{Q}$. But we know that $\mathbb{Q}\setminus \{0\}$ is a group with respect to multiplication.