The answer is 70:
1) If there are 5 kinds of fruit, there are 10 different pairs of fruit kinds (4+3+2+1). The questions specifies that you need to select exactly two kinds of fruit to build the collection.
2) From 8 fruit there are 7 ways to choose how many of the 1st kind to choose and how many from the 2nd kind to choose (7+1, 6+2, 5+3, 4+4, 3+5, 2+6, 1+7). So you'd choose 7 apples and 1 orange, for example.
Note: These are not 9 ways as I suppose you calculated, because if you choose 8+0 or 0+8 of each fruit, you'll have only 1 kind, not as the question says exactly two kinds.
multiply the probabilities 7*10 and you get 70 :)