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Can anyone help me simplify this boolean expression?

ABC' + A'BC + A'B'C'

EDIT: (only using AND gates (multiply [(x)(x)]) and OR gates (addition [+]))

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I think this is the simpliest form of the expression.

You can verify this through Karnaugh map(http://en.wikipedia.org/wiki/Karnaugh_map)

A Karnaugh map of this question is shown below and it's clear to see there's cancellation.

$ \begin{array}{|c|c|c|c|c|} \hline C\backslash \text{AB} & 00 & 01 & 11 & 10 \\ \hline 0 & 1 & 0 & 1 & 0 \\ \hline 1 & 0 & 1 & 0 & 0 \\ \hline \end{array} $

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