Here's the equation I need to solve (for $x$)...


is there a solution in terms of the constants $r$ and $b$?


  • 1
    $\begingroup$ Solve $\large \sqrt{\vphantom{\Large A}x^{2} - 1\,} + \mu\,\arccos\left(1 \over x\right) = \nu$ first. $\large\mu \equiv {1 \over br^{2}} - 1$ and $\large\nu \equiv {\pi \over 2br^{2}}$. $\endgroup$ – Felix Marin Sep 27 '13 at 0:05

Start by writing $$x=r\sec t$$ This eliminates the square root and the inverse cosine in terms of $\tan t$ and t.


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