Thanks to both Mufasa and Ron Gordon, I now understand when I difficultly came from, misunderstanding of the term vertically.
A rocket takes off vertically from the ground. 2000 ft. away, a camera captures it image. The rocket lift-off vertically to the position equation $s=50t^2$. Find the rate of change of the angle of the camera at 10 seconds after lift-off.
I am having trouble solving this problem. Also, a bit unsure if I fully understand the language used in the problem.
I know that the rocket lift off vertically, and I know the graph of the position function $s$.
I know to use the right half of the graph, otherwise time would being going backwards.
However, how to give the angle is puzzling me, from the camera's reference point. I know how to use the arc length to find the angle, but only for circles.
Now, I understand that vertically means a straight line, but how does one solve it if it doesn't follow the strict meaning of vertically, and insteads follows a parabola?