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I am wondering if the third to last equation is correct, where i factored out the $(-1)^k$. The first term is inside the parenthesis is $(-1)^{-1}$. Is this correct? If I multiply it out again,, wont the (-1)'s cancel? I'm not 100% sure even though i proved it. I am assuming $(-1)^k$ multiplied by (-1)^-1 is (-1)^(k-1) Proof

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    $\begingroup$ Correct${}{}{}$ $\endgroup$
    – peterwhy
    Sep 19, 2013 at 4:13
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    $\begingroup$ Agreed. Well done. $\endgroup$
    – André Nicolas
    Sep 19, 2013 at 4:44

1 Answer 1

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Your proof is completely correct.

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  • $\begingroup$ where did the $(-1)^k$ go between lines 1 and 2 $\endgroup$
    – Benny
    Sep 15, 2022 at 11:33

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